Capacitor calculation for high pass filter

If I want to stick a simple passive high pass filter onto a tweeter (and nothing else), how do I calculate what micro-farad (uF) and volage I need for any given frequency?

*** more complex crossover calculations/guides are easy to find, but too advanced for my needs.
 
For an RC network, the formula is: f = 1 / ( 2 x Pi x R x C )

Rearranging to solve for C, we get: C = 1 / ( 2 x Pi x R x f )

where Pi is 3.14

We always must use the proper units, in order to get the right answer:
f in Hz
R in Ohms
C in Farads

and 1F = 1,000,000 uF
 
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There's a misunderstanding about the capacitor polarity. All that is required is to connect two equal
polarized capacitors in anti-series, to form an unpolarized capacitor.

It does not matter where in the circuit branch the capacitors are connected. The tweeter could be on either side
of the series capacitors, or in between them. It would all work exactly the same.

The tweeter + marking means that when a positive voltage is applied to that terminal relative to the unmarked terminal,
the cone will move forward.
 
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New member, wickette, appears not to be looking for an LC filter calculator - he refers to a single capacitor high pass filter.

So, this is the one I would choose from your search list:

https://www.claredot.net/en/sec-Sound/high-pass-cross-over-6dB.php

@ wickette: You asked about voltage. Provided it's a domestic speaker, choose a minimum rating of 70 V DC - and it's perfectly OK to go higher.
)Thank you! My powerful amp is using a 30V DC PSU 140watt RMS out, 100V cap is enough?
 
So, obviously I'm a super newb, and Im playing with cheap 2,3,4 way coaxial speakers. My assumption was the woofer was 8ohm, and whatever was in the center housing was 8ohms since all of these speakers just have a single capacitor. But I don't think this was a correct assumption. Would I have anyway of knowing the tweeter impedance without breaking anything?
I wanted cancel out the brightness by changing the capacitors so the cut off is over 8k-10k on the tweetiest speakers. ...And if that did't work stick a resistor next to the capacitor to hush them up... all bad ideas right?
 
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Here you have a table with the values corresponding to the simplest of filters, only C.
If it's unpolarized it will go either way, if it's polarized the positive side of electrolytic C goes to the positive side of the tweeter.

http://audiocarpy.blogspot.com/2014/01/capacitores-para-drivers-y-tweeters.html


Wow, the bold highlighted part is wrong, yet another proof that the internet is full of crap.
It is a first order filter ( 6 dB/octave.)

http://audiocarpy.blogspot.com/2014/01/capacitores-para-drivers-y-tweeters.html

But the table attached to that link is OK, the OP can check it with this online calculator.


https://www.pcpaudio.com/pcpfiles/doc_altavoces/filtros_pasivos/filtrospasivos.php#filtro2

Sorry for the mistake. The intention was to help and I did not pay too much attention to what I copied



" Some important information and tips before installing the capacitor:

1· The capacitors have to be installed on the positive lead of the audio component.

2- There are polarized and depolarized capacitors.
The polarized ones: they have to be connected in series with the cable, that is, the negative part (shorter leg and a mark with a white stripe) has to be connected in the direction of the cable that goes to the amplifier and the positive part has to be connected towards the positive pole of the speaker, driver or super tweeter (the positive pole has the longest leg)


The depolarized: they can be connected in any way because they do not have polarity. "