How to calculate speaker box volume for boom box i.e. two speakers

Just thinking out loud: in this case each speaker will have the double volume needed, isn‘t it?
I mean if a single cone would need for example 1 liter of internal volume doing that would result in 2 speakers in 2 liters. Doesn’t sound right
 
Just thinking out loud: in this case each speaker will have the double volume needed, isn‘t it?
I mean if a single cone would need for example 1 liter of internal volume doing that would result in 2 speakers in 2 liters. Doesn’t sound right
Why not? He asks rhetorically........😉 Assuming no box aspect ratio high enough to create eigenmodes (some form of TL), then the box's air mass 'spring' is presumed to have a ~uniform particle density, so double the driver's compliance (Vas), not effective piston area (Sd), requires doubling the box's air mass 'spring' to compensate.
 
Just thinking out loud: in this case each speaker will have the double volume needed, isn‘t it?
I mean if a single cone would need for example 1 liter of internal volume doing that would result in 2 speakers in 2 liters. Doesn’t sound right
Another way to see it:

* One speaker 1 liter means speaker works against air springiness/stiffness.

* You think one speaker in 2 liter box works against half the stiffness .... and that would be true if speaker were alone.

* but if there is a second speaker, compressing that air, air is not "passive" any more, but "active" ... it´s being compressed also by the second speaker.

In the grand total, it works as if each speaker is working only with its own 1 liter space.